It's probably silly to start remote-lawyering with Mr Torvalds of all people, but that is obviously false, and (also obviously) he knows it.

If it acts exactly like a function, show me its prototype, and how you would call it through a function pointer. I'll be here, waiting while thumbing through my old K&R, or something ...

Also, when using variable-length arrays (which are being phased out, but they are in for instance C99) this works:

    #include <stdio.h>
    #include <stdlib.h>
    #include <string.h>

    int main(int argc, char *argv[])
    {
       size_t arglens[argc];
       for (size_t i = 0; i < sizeof arglens / sizeof *arglens; ++i) {
         arglens[i] = strlen(argv[i]);
       }
       printf("Computed %zu lens:\n", sizeof arglens / sizeof *arglens);
       for (size_t i = 0; i < sizeof arglens / sizeof *arglens; ++i) {
         printf("%zu: '%s' is %zu\n", i, argv[i], arglens[i]);
       }
       return 0;
    }

Compile (as C99!) and run:

    $ gcc -o arglens -std=c99 arglens.c
    $ ./arglens foo bar baz fooofooofoo
    Computed 5 lens:
    0: './arglens' is 9
    1: 'foo' is 3
    2: 'bar' is 3
    3: 'baz' is 3
    4: 'fooofooofoo' is 11

Notice how sizeof is computing the size of a run-time sized array. Very much unlike a function.

Edit: fix indent for code formatting (hard tabs don't work).