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I am not confused. You're engaged with the particulars, whereas my post is mostly about the Zout == Zin, and not specifically about headphones.

> Why are you even considering the case of a zero Ohm load with a 16 Ohm source impedance?

For completeness of the analysis. If we hold Zout constant, and likewise the output voltage of the voltage source, and consider a Zin of zero, in that case, power transfer is mimimal (zero). Likewise power transfer goes to zero for large Zin. In between those is the Zout = Zin point where the maximum transfer is obtained by the load from the source. This is part of explaining of what is Zout = Zin about; what is maximized.

For instance consider a R1 resistor in series with a battery. You may not change the battery or R1. For what value of R2 can you get R2 to dissipate the most power? The solution is R2 = R1.

It is useful to think about what happens if we make R2 zero; why wouldn't we consider it. A certain current will flow through a zero ohm R2, but it will not be dissipating any power. From there as we increase R1, the power dissipation curve rises. At R1 = R2, it turns around, and then converges to zero as R1 grows larger.



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